Відео

I enjoyed your video please don't stop making videos

Best. i watched a lot of videos but it was the best😭

neff force

Erm what the sigma.

Please, can JG make a video on longitude and latitude?

I really and quickly understand from you. Thank-you.

:0.01

Who is here Zambia 2024

9:30

I'm not even in college. I just wanted to know what the hell this was.

I love this guy bro❤

Im just gonna be honest I’m watching this at 3 am on 3 hours of sleep but this video still makes more sense than when my science teacher explains this.

I clicked because I knew it would be something important . I mean what is 53mins that I can't spare!

May God bless you sir you really help

wait dont you teach latin too??

Let say we get a 66.7% can we round of this into 17% ?

I have learned everything from this man EXCEPT organic chemistry

V inital=(MFinal x VFinal)/(M Iinital) or Vfinal=(Minital x Vinital)/(M final)

Alllll went to shit by 12 minutes.

The 3D version of this is spherical harmonics which have a lot to do with orbitals

For the first question I took the P = MA and applied that to the Astro dude so V = P/M is that wrong

You make it really easy to understand calculus.

Bro I tried to do this alone especially the last one but I'm not understanding how you calculated with that percentage

dont you need to seperate into 2 case to do at 8:46, cuz you dont know whether x+3 is negative tho?

Thank you so much for this video. I spent probably close to an hour trying to decifer this via articles online before finding the actual answers here

Soc Cah Toah.

Can someone please explain how can the length of a vector (cross product) which is a “1D line” be equal to the area which is 2D this is somehow confusing to me?

in the last example, you have to show the amide linkage in your polymer notation, which you missed.

52:50 can someone explain how or why does square root = 15th root

Legends watch after exam... to verify only📍

i love you

Exam after 8H ,anyone else?

You are the most genius teacher in the world thank you for helping me!!

46:38 it’s x⁶ not x^4 ;-; HOW DID HE STILL GET IT RIGHT BUT THE CALCULATION ISNT THE SAME WTH x⁸ -- = x⁶ x² I think I get it! He’s using the index on the left there, I was so confused because I thought he was subtracting it from top to bottom like he usually does. I wish the video was more specific ;-; because it made me so confused at first. I know that he said he used a different method but I didn’t expect it to be that way, I do know now. 47:25 different one but here I thought he already taught us that, to take away from the bottom. Regardless, at least I understood the problem.

500,000 cm - > m 500000³ cm x 1m³ 100 cm Cm. Cm. Cm 500,000 cm³ x 1m³

Ова е за мој мозок😊

I have an Exam in 2 days so I am watching the whole list of videos

maybe specify that we're looking for a sample SD as opposed to the population SD / which is why you're using n-1 , as opposed to just N

Good Work

Hats off❤❤

OCT, you are a literal legend!😊 Thanks for all the advice. I’ll definitely try some of your suggestions

I love to be part of your chemistry class

Wbo else is here because you know you're teacher always bring ts

I sat through a 2 hour lecture on this and left confused, and bro explained the entire thing crystal clear in 13 minutes 😭

You're amazing dude. I can't stomach the Pearson's lecture in MyMathLab.... Who ever made those lesson thought i need to make it as impossible as possible to justify getting pay. I need to make the new students feel I'm so smart and they so dumb that can understand more than 3% of what I'm saying. I just listen to those video to know how they will ask the question in the quiz then I come to your channel to actually learn.

This was just a life-saviour!!! 🙌🏻🙌🏻 I was panicking so much that I didn't know this concept but you saved me!!! Highly recommended!! 🙌🏻❤️

thank God for these videos, cuz my chem teacher does not know how to teach

1:31 how did he get 4 moles??

ua-cam.com/play/PLfa-2G0QZHxxRyuD62QqqPSXj7uxB-gAy.html&si=6uWKoh81lfikNPRB

This is a great video. It was so helpful.